Some work on binops
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@ -1,6 +1,10 @@
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use std::rc::Rc;
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use std::collections::HashMap;
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macro_rules! bx {
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($e:expr) => { Box::new($e) }
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}
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use schala_lang::parsing;
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pub struct TypeContext {
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@ -10,7 +14,7 @@ pub struct TypeContext {
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#[derive(Debug, PartialEq, Clone)]
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pub enum Type {
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Const(TConst),
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Func(Vec<Type>),
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Func(Box<Type>, Box<Type>),
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Void
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}
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@ -78,11 +82,17 @@ impl TypeContext {
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&FloatLiteral(_) => Ok(Const(Float)),
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&StringLiteral(_) => Ok(Const(StringT)),
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&BoolLiteral(_) => Ok(Const(Bool)),
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&BinExp(ref op, ref lhs, ref rhs) => {
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let _op_ty = self.infer_optype(op);
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let _lhs_ty = self.infer(lhs);
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let _rhs_ty = self.infer(rhs);
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Ok(Const(Unit))
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&BinExp(ref op, ref lhs, ref rhs) => { /* remember there are both the haskell convention talk and the write you a haskell ways to do this! */
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match self.infer_optype(op)? {
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Func(box t1, box Func(box t2, box t3)) => {
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let lhs_ty = self.infer(lhs)?;
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let rhs_ty = self.infer(rhs)?;
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self.unify(t1, lhs_ty)?;
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self.unify(t2, rhs_ty)?;
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Ok(t3)
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},
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other => return Err(format!("{:?} is not a binary function type", other))
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}
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},
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/*
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BinExp(Operation, Box<Expression>, Box<Expression>),
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@ -107,7 +117,7 @@ impl TypeContext {
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fn infer_optype(&mut self, _op: &parsing::Operation) -> TypeResult<Type> {
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use self::Type::*; use self::TConst::*;
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//this is a shim; not all ops are binops from int -> int -> int
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Ok(Func(vec![Const(Int), Const(Int), Const(Int)]))
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Ok(Func(bx!(Const(Int)), bx!(Func(bx!(Const(Int)), bx!(Const(Int))))))
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}
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fn type_from_anno(&mut self, anno: &parsing::TypeName) -> TypeResult<Type> {
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use self::parsing::TypeSingletonName;
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